select c.categories_id, cd.categories_name from categories c JOIN categories_description cd ON ( c.categories_id = cd.categories_id ) where cd.language_id = '1' order by cd.categories_name
[TEP STOP]
2006 - MySQL server has gone away
select 1 from sessions where sesskey = 's0gflim7snvu4be3vbsiglapm2'